percentage Model Questions & Answers, Practice Test for ibps rrb po officer scale 1 prelims 2024

ibps rrb po officer scale 1 prelims 2024 SYLLABUS WISE SUBJECTS MCQs

Number System

Lcm & Hcf

Simplification

Percentage

Time & Work

Time & Distance

Question :6

A's salary was increased by 40% and then decreased by 20%. On the whole A's salary is increased by

Answer: (d)

Let the salary of A be 100.

A's salary after 40% increase will be

$100 + {100 + 40}/100 = 140%$

A's salary after 20% decrease will be

$140 - {140 × 20}/100 = 112$

On a whole A's salary is increased by

= $({112 - 100}/100) × 100 = 12%$

So, option (d) is correct.

Short cut method

+ 40 – 20 + $(40 × -20)/100$ =20 - 8 = 12%↑ se.

Question :7

A screw driver and a hammer currently have the same price. If the price of a screw driver rises by 5% and the price of hammer goes up by 3%, then how much more will it cost to buy 3 screw drivers and 3 hammers ?

Answer: (a)

Let the original price of a screw driver and a hammer be Rs. 100 each.

Then, price of 3 screw drivers and 3 hammers = Rs. 600

Now, after increase of 5%, the price of 3 screw drivers = Rs. 315

And after 3% increase the price of 3 hammers = Rs. 309

Increased price of 3 hammers and 3 screw drivers = Rs. 624

Therefore, % increase in price = $24/600 × 100 = 4%$

Question :8

Two candidates fought an election. One of them got 64% of the total votes and won with 992 votes. What was the total number of votes polled ?

Answer: (e)

Votes obtained by winner candidate = 64%

Votes obtained by loser candidate

= (100 – 64) = 36%

Difference of votes = (64 – 36) = 28%

According to question,

Total votes = ${992 × 100}/28$ = 3542

Question :9

A person's salary has increased from Rs.7200 to Rs. 8100. What is the percentage increase in his salary?

Answer: (d)

Percentage increase in salary

= ${8100 - 7200}/7200 × 100$

= $900/7200 × 100 = 12.5% = 12{1}/2$ %

Question :10

Two vessels contain equal quantities of 40% alcohol. Anil changed the concentration of the first vessels to 50% by adding extra quantity of pure alcohol. Balu changed the concentration of the second vessels to 50% replacing a certain quantity of the solution with pure alcohol. By what percentage is the quantity of alcohol added by Anil more than that replaced by Balu?

Answer: (b)

Solution = 100 ml and Alcohol = 40 ml

For first vessel

${40 + x}/{100 + x} = 1/2$

so, x = 20ml

For second vessel

${40 + 3/5y}/{100 + 2/5y} = 1/2$

so, y = 25ml

Required percentage = $5/25 × 100$ = 20%

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